ANGLES AND GEOMETRY PART 2
AB and CD intersect each other at O. Given ∠EOA = 90°, ∠EOC = x, ∠BOC = y and ∠BOD = 2y + 30. Find the value of x and y and ∠AOD Since CD is a straight line, therefore the sum of 2y + 30 and y must be 180 degree Hence, 2y + 30 + y = 180 3y + 30 = 180 3y = 150 y = 50° Also AB is a straight line therefore the sum of angles EOA, EOC and BOC must be 180 degree. Hence, 90 + x + y = 180 90 + x + 50 = 180 x + 140 = 180 x = 40° Therefore, x = 40° and y = 50°.